MathGroup Archive 1990

[Date Index] [Thread Index] [Author Index]

Search the Archive

D and sinh'; s/c vs. s*c^(-1).


I suspect that 
cosh'[....] := .... defines the derivative with respect to its argument,
in this case, 2x, as 2*sinh[2*x]. But to take the derivative with respect
to x, you get 2*sinh[2*x] * D[2*x,x]  or 4.

As for c^n_/s^n_ -> t^(-n),  I think your pattern has a division
in it, but your expression has a multiplication.
c^n*s^(-n).  I think you need a rule for c^n_*s^m_ -> somefunctionof(n,m).

Good luck.
 Richard Fateman








  • Prev by Date: Coefficient
  • Next by Date: Coefficient[]
  • Previous by thread: Re: Coefficient
  • Next by thread: Coefficient[]