Re: Help: how to disp. 3-D vectors

*To*: mathgroup at yoda.physics.unc.edu*Subject*: Re: Help: how to disp. 3-D vectors*From*: villegas*Date*: Fri, 8 Oct 93 08:41:04 -0500

I made a mistake in my posting below: > Date: Wed, 6 Oct 93 08:01:07 -0500 > From: villegas > Subject: Re: Help: how to disp. 3-D vectors > To: mathgroup at yoda.physics.unc.edu .. > Using this notation, the desired Arrow object would be > > Arrow[#1, #1 + #3 * #2/(#2 . #2)] (* assuming #2 is not a unit vector *) .. > Let's make a sample list of arrow-specifications and show how to > form and render the Arrows. In this example, I used direction > vectors, so I did not need to divide #2 by the norm (#2 . #2) as > above. But your data list might need the more general form above. Throughout this response, I used (#2 . #2) instead of Sqrt[#2 . #2] for the norm of the vector that provided the direction. I realized this when I read Tom Wickham-Jones' response. Apologies for the confusion. Robby Villegas villegas at wri.com