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Re: Help: how to disp. 3-D vectors

• To: mathgroup at yoda.physics.unc.edu
• Subject: Re: Help: how to disp. 3-D vectors
• From: villegas
• Date: Fri, 8 Oct 93 08:41:04 -0500

I made a mistake in my posting below:

> Date: Wed, 6 Oct 93 08:01:07 -0500
> From: villegas
> Subject: Re: Help: how to disp. 3-D vectors
> To: mathgroup at yoda.physics.unc.edu

..

> Using this notation, the desired Arrow object would be
> 

> Arrow[#1, #1 + #3 * #2/(#2 . #2)]   (* assuming #2 is not a unit vector *)

..

>    Let's make a sample list of arrow-specifications and show how to
> form and render the Arrows.  In this example, I used direction
> vectors, so I did not need to divide #2 by the norm (#2 . #2) as
> above.  But your data list might need the more general form above.


Throughout this response, I used (#2 . #2) instead of Sqrt[#2 . #2] for the
norm of the vector that provided the direction.  I realized this when I
read Tom Wickham-Jones' response.

Apologies for the confusion.

Robby Villegas
villegas at wri.com