RE: Negative Area: Definitive Answer (not)

*To*: mathgroup at christensen.cybernetics.net*Subject*: [mg223] RE: [mg213] Negative Area: Definitive Answer (not)*From*: Chip Sample <sample at shire.ac.arknet.edu>*Date*: Wed, 23 Nov 1994 12:38:21 CST

I've figured it out! Your example gives the wrong answer as shown here, In[10]:= Integrate[1/(A+B Cos[x])^2,{x,0,2 Pi}]/.{A->2,B->1} Out[10]= -4 Pi --------- 3 Sqrt[3] but if you reverse the roles of A and B you get the right answer. In[11]:= Integrate[1/(B+A Cos[x])^2,{x,0,2 Pi}]/.{A->1, B->2} Out[11]= 4 Pi --------- 3 Sqrt[3] So clearly, you just put your A's and B's in the wrong places! ;o) Chip