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RE: Negative Area: Definitive Answer (not)
*To*: mathgroup at christensen.cybernetics.net
*Subject*: [mg223] RE: [mg213] Negative Area: Definitive Answer (not)
*From*: Chip Sample <sample at shire.ac.arknet.edu>
*Date*: Wed, 23 Nov 1994 12:38:21 CST
I've figured it out! Your example gives the wrong answer as shown here,
In[10]:=
Integrate[1/(A+B Cos[x])^2,{x,0,2 Pi}]/.{A->2,B->1}
Out[10]=
-4 Pi
---------
3 Sqrt[3]
but if you reverse the roles of A and B you get the right answer.
In[11]:=
Integrate[1/(B+A Cos[x])^2,{x,0,2 Pi}]/.{A->1, B->2}
Out[11]=
4 Pi
---------
3 Sqrt[3]
So clearly, you just put your A's and B's in the wrong places! ;o)
Chip
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