[Date Index]
[Thread Index]
[Author Index]
Re: (1)^(3/4) > (1+I)/Sqrt[2]
 To: mathgroup at christensen.cybernetics.net
 Subject: [mg566] Re: [mg557] (1)^(3/4) > (1+I)/Sqrt[2]
 From: bob at zim.uoregon.edu (Robert Zimmerman)
 Date: Sat, 18 Mar 95 15:48:03 0800
Question
Does anybody know a core or standard package command that makes
transformations like (1)^(3/4) > (1+I)/Sqrt[2] ? I would be
happy with a method that works as well as, say,
One possible solution,
rule=( 1)^p_:> (Cos[ p Pi]+I Sin[p Pi] )
test = ( 1 )^(3/4)
test /.rule
(1)^(p_) :> Cos[p*Pi] + I*Sin[p*Pi]
(1)^(3/4)
(1 + I)/2^(1/2)
Robert L. Zimmerman
Institute of Theoretical Science
University of Oregon
Eugene Oregon 97403
Prev by Date:
New Book  MATHEMATICA FOR PHYSICS
Next by Date:
Re: how to pick out alternating columns and rows in a matrix?
Previous by thread:
(1)^(3/4) > (1+I)/Sqrt[2]
Next by thread:
Re: (1)^(3/4) > (1+I)/Sqrt[2]
