MathGroup Archive 1996

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Trig Simplifications

  • To: mathgroup at smc.vnet.net
  • Subject: [mg3704] Re: Trig Simplifications
  • From: hohmuth at cipserv1.physik.uni-ulm.de (Lars Hohmuth)
  • Date: Wed, 10 Apr 1996 02:10:51 -0400
  • Organization: Uni Ulm
  • Sender: owner-wri-mathgroup at wolfram.com

In article <4ka54g$sai at dragonfly.wolfram.com> Alexander Casti <arc at carmen.phys.columbia.edu> writes:
>From: Alexander Casti <arc at carmen.phys.columbia.edu>
To: mathgroup at smc.vnet.net
>Subject: Trig Simplifications
>Date: 8 Apr 1996 04:36:32 GMT


>Basically my question is how to get mathematica to write

>Exp[I x] in place of Cos[x] + I Sin[x]

>Suppose I have the expression  

>In[1]: f[x_]= Cos[x] + I Sin[x] - Cos[2 X] + I Sin[2 X]

>I would like mathematica to simplify this into

>f[x_]= Exp[I X] - Exp[2 I X]

>I tried the substitution command

>In[2]: % ./ Cos[X]+I Sin[X]-> Exp[I X] and it returned
>Out[2]: E^{I X}  - Cos[2 X] + I Sin[2 X]

>So, it seems as though this simple minded approach is not
>enough for mathematica to understand the substitution rules
>for powers of complex exponentials other than the one I 
>explicitly gave.
>In addition, commands like Simplify[Blah] do not seem to do
>the trick either.  I believe I have the trigonometry package
>loaded in (via the command Needs["Algebra`Trigonometry`"]).
>What must I do ? 

>Thanks for your time.

>Alex

If you have the Trigonometry package loaded, try the command 
TrigToComplex[Cos[x] + I Sin[x]].


CU,


Lars







==== [MESSAGE SEPARATOR] ====


  • Prev by Date: Re: Trig Simplifications
  • Next by Date: DSolveConstants question
  • Previous by thread: Re: Trig Simplifications
  • Next by thread: Re: Trig Simplifications