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Re: Re: Speed of dot product in Mathematica


Twice as fast and simpler than my previous posting is the following  
variant of Michael Trott's code  -  using Range instead of Table.

SteppedTake2[list_, {start_, finish_, step_}]:=
list[[Range[start,finish, step]]]

Timings

SteppedTake[list, {20,9000,5}];//Timing (*my previous*)
SteppedTake2[list, {20,9000,5}];//Timing

Allan Hayes
hay at haystack.demon.co.uk
http://www.haystack.demon.co.uk


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