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Re: multiplying sets

  • To: mathgroup at smc.vnet.net
  • Subject: [mg2969] Re: multiplying sets
  • From: Jorma.Virtamo at vtt.fi (Jorma Virtamo)
  • Date: Wed, 17 Jan 1996 03:09:50 -0500

Tommi Salminen <titosa at uta.fi> wrote:
>
> I have a problem as follows:
> 
> I have a set, for instance: s={{a,b,c},{d,e},{f,g}}, and I would like
> to get a set t, that includes all possible multiplications between
> those three sets {a,b,c}, {d,e} and {f,g}. 
> 
> Of course, one way would be :
> 
>      Outer[Times,{a,b,c},{d,e},{f,g}], but I'd like find some kind
> of a more reasonable way to do it, because it would be just a part
> of a larger program. Anyway, it doesn't have to be some elegant way;
> if it works, it's OK.
> 

I don't know what is wrong with the Outer. If you define

   s1={a,b,c};
   s2={d,e};
   s3={f,g};

then Outer yields:

   Outer[Times,s1,s2,s3] // Flatten
 
  {a d f, a d g, a e f, a e g, b d f, b d g, 
   b e f, b e g, c d f, c d g, c  e f, c e g}

Another way to write the same is for instance:

   s3#& /@ s2#& /@ s1 // Flatten

with an identical result:

  {a d f, a d g, a e f, a e g, b d f, b d g, 
   b e f, b e g, c d f, c d g, c e f, c e g}

Whether this is more reasonable way to write the expression
is rather a matter of taste. Personally, I would prefer Outer, 
which also seems to be faster. Maybe you want something faster
than Outer?

-- Jorma Virtamo


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