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Re: Function


Roberto,

this will do it:

In[1]:=
(Drop[#,1]/Drop[#,-1])&[Array[a,10]]
 Out[1]=
 a[2]  a[3]  a[4]  a[5]  a[6]  a[7]  a[8]  a[9]  a[10]
{----, ----, ----, ----, ----, ----, ----, ----, -----}
 a[1]  a[2]  a[3]  a[4]  a[5]  a[6]  a[7]  a[8]  a[9]
-- 
Regards,

Roger Jones

(rmj at leland.stanford.edu)

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