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MathGroup Archive 1996

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Re: cancel function

  • To: mathgroup at
  • Subject: [mg5276] Re: [mg5212] cancel function
  • From: BobHanlon at
  • Date: Mon, 18 Nov 1996 02:30:22 -0500
  • Sender: owner-wri-mathgroup at

eqn1 = ( a E^(I t w) (b + c x) == 0 )

   I t w
a E      (b + c x) == 0

eqn1/E^(I t w)

 -I t w     I t w
E       (a E      (b + c x) == 0)

Note that this is dividing an equation by an expression which is undefined.

Cancel[eqn1/E^(I t w)]

 -I t w     I t w
E       (a E      (b + c x) == 0)

Applying Cancel doesn't change anything since there is nothing to cancel.
a replacement rule:

eqnSimplify = (a_ (lhs_ == rhs_) -> a lhs == a rhs);
eqn1/E^(I t w) /. eqnSimplify

a (b + c x) == 0


Subj:  [mg5212] cancel function
From:  Ralheid at
To: mathgroup at

I cannot seem to get mathematica to cancel the exponetial function in the
following relationship;

in(1) =  eqn1 = a E^(I w t )(b + c x) == 0
out(1)= a E^(I w t ) (b + c x) == 0

in(2) = eqnw = Cancel[eqn1/E^(I w t )]
out(2) = E^(-I w t )( a E^(I w t )(b + c x) == 0)

I seem to think that cancel should reduce above to:

out(2) = eqnw = (b + c x) == 0

any help would be appreciated.

R. Alheid

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