|
[Date Index]
[Thread Index]
[Author Index]
Re: cancel function
- To: mathgroup at smc.vnet.net
- Subject: [mg5276] Re: [mg5212] cancel function
- From: BobHanlon at aol.com
- Date: Mon, 18 Nov 1996 02:30:22 -0500
- Sender: owner-wri-mathgroup at wolfram.com
eqn1 = ( a E^(I t w) (b + c x) == 0 )
I t w
a E (b + c x) == 0
eqn1/E^(I t w)
-I t w I t w
E (a E (b + c x) == 0)
Note that this is dividing an equation by an expression which is undefined.
Cancel[eqn1/E^(I t w)]
-I t w I t w
E (a E (b + c x) == 0)
Applying Cancel doesn't change anything since there is nothing to cancel.
Use
a replacement rule:
eqnSimplify = (a_ (lhs_ == rhs_) -> a lhs == a rhs);
eqn1/E^(I t w) /. eqnSimplify
a (b + c x) == 0
FORWARDED MESSAGE:
Subj: [mg5212] cancel function
From: Ralheid at aol.com
To: mathgroup at smc.vnet.net
I cannot seem to get mathematica to cancel the exponetial function in the
following relationship;
in(1) = eqn1 = a E^(I w t )(b + c x) == 0
out(1)= a E^(I w t ) (b + c x) == 0
in(2) = eqnw = Cancel[eqn1/E^(I w t )]
out(2) = E^(-I w t )( a E^(I w t )(b + c x) == 0)
I seem to think that cancel should reduce above to:
out(2) = eqnw = (b + c x) == 0
any help would be appreciated.
R. Alheid
Prev by Date:
Wavelets...
Next by Date:
Re: Inverse of Error Function
Previous by thread:
cancel function
Next by thread:
labelling contours
|