Re: programming competition Correction
- To: mathgroup at smc.vnet.net
- Subject: [mg4951] Re: [mg4904] programming competition Correction
- From: Allan Hayes <hay at haystack>
- Date: Mon, 7 Oct 1996 02:02:17 -0400
- Sender: owner-wri-mathgroup at wolfram.com
Please change line 6 in the code that I gave from
If[n<2, {#1},
to If[n<1, {#1},
giving
linearInterpolate2[ li_List, m_ ] :=
Block[{},
Append[
Join@@Partition[ li, 2,1,
( n=Floor[Sqrt[(#2-#1).(#2-#1)//N]/m];
If[n<1,
{#1},
Table[#1 + k #2, {k,0,n}]&[#1,(#2-#1)/(n+1)],
]
)&
],
Last[li]
]
];
(the error crept in because of changing from Ceiling to Floor)
I time it (and check it!) against the fastest code in Xah Lee's
posting "[mg4900] Re: programming competition", due to
espen.haslund at fys.uio.no (Espen Haslund):
linearInterpolateEH2[ li_List, maxLength_ ]:=
Module[{p1, p2, n},
Append[Join @@ Table[{p1, p2} = li[[{i, i+1}]];
n = Max[Ceiling[Sqrt[#.#]&[N[p2-p1]]/maxLength],1];
Table[p1+(p2-p1)j,{j,0,1-.5/n,1./n}],
{i,1,Length[li]-1}], Last[li] ]
]
li = Table[{Random[], Random[]}, {1000}];
maxLength = .1;
a4 = Timing@ linearInterpolateEH2[ li, maxLength];
a5 = Timing@ linearInterpolate2[ li, maxLength];
First /@ {a4,a5}
SameQ@@ Last /@ SetPrecision[{a4,a5},5]
{21.3 Second, 14.8333 Second}
True
Allan Hayes
hay at haystack.demon.co.uk
URL:haystack.demon.co.uk
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