Re: Help me please!!!
- To: mathgroup at smc.vnet.net
- Subject: [mg5815] Re: [mg5770] Help me please!!!
- From: BobHanlon at aol.com
- Date: Wed, 22 Jan 1997 00:44:17 -0500
- Sender: owner-wri-mathgroup at wolfram.com
>> I must invert this function: y = (x^2) + x for x >= 0 In Mathematica: Select[Solve[ y == x^2 + x, x ], (x /. (# /. y -> 1)) > 0&] or by hand just use quadratic equation for solving x^2 + x - y == 0 and select solution which provides nonnegative values for x (+Sqrt[]). Bob Hanlon