Re Need a new type of Hold

*To*: mathgroup at smc.vnet.net*Subject*: [mg7623] Re [mg7538] Need a new type of Hold*From*: Ersek_Ted%PAX1A at mr.nawcad.navy.mil*Date*: Fri, 20 Jun 1997 16:15:57 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

In [mg7538] Dave Wagner replied to my desire for a new type of Hold (see below). My original correspondence was [mg7499]. I recently figured out how to change HoldForm so that it works pretty much the way I want the new type of Hold to work. The only problem is that I lose the usual implementation of HoldForm along the way. Can someone out there build this feature without messing up HoldForm. (*-------------------------------------------------*) In[1]:= Unprotect[HoldForm]; HoldForm/:g_[a___,HoldForm[expr_],b___]/; (g=!=FullForm && g=!=Set && g=!=SetDelayed && g=!=List && g=!=Part) := g[a, expr, b] (* "a___" and "b___" are BlankNullSequences *) In[2]:= foo=HoldForm[z+2+d+a+3] Out[2]= z+2+d+a+3 In[3]:= foo-d+4 Out[3]= 9+a+z In[4]:= HoldForm[z+2+d+a+3] //FullForm Out[4]//FullForm= HoldForm[Plus[z, 2, d, a, 3]] In[5]:= foo+b Out[5]= 5+a+b+d+z (*________________________*) Originally I didn't want to have any type of Hold to show up in the FullForm. I couldn't make it work that way, but that isn't important. Some important points: - This should work on any expression, not only those with Plus for a Head. - I want to use the held results later on without releasing the hold. - When the held result is used in later calculations, the hold should be released automatically. In the above I included ( g=!=SetDelayed && g=!=List && g=!=Part ). This isn't needed for the performance I wanted earlier, but I thought it was an enhancement. Ted Ersek ersek_ted%pax1a at mr.nawcad.navy.mil -------------------------------------------------------- Dave Wagner replied: >At first I thought that what you really want to do is define your >own addition operator, but then I decided that what you are trying to >do is fundamentally inconsistent with the way >Mathematica works (I won't say "impossible", since everytime I say t>hat some smart-aleck figures out a way to do it.) > >Here's why: i>n your first output, the 2 and the 3 don't combine. Yet, in the second >output, they have combined with the 9. What should happen if I type >"foo + b"? Should the result be "z+2+d+a+3+b" or should it be >"5+a+d+a+b". Or should it be something else? The fact is, if you want >the 2 and 3 to combine, then they should have combined in the first >output; if you want the order of the terms to be strictly maintained, >then the second output should have been "z+2+d+a+7" (let's assume that >it's okay to combine adjacent terms). One or the other, you can't >have it both ways. > >By the way, if it's a non-associative addition operator that you're >after, I don't recommend removing the Orderless attribute from Plus, >or you'll break a lot of other things. > > Dave Wagner > Principia Consulting

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