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MathGroup Archive 1997

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Using Sqrt[x_]/y_ ->

  • To: mathgroup at smc.vnet.net
  • Subject: [mg7314] Using Sqrt[x_]/y_ ->
  • From: sergio at scisun.sci.ccny.cuny.edu (Sergio Rojas)
  • Date: Fri, 23 May 1997 01:41:48 -0400 (EDT)
  • Organization: City College Of New York - Science
  • Sender: owner-wri-mathgroup at wolfram.com

(*--> Hello folks,   *)
	(*--->   In Mathematica 2.2, using:  *)

Needs["Calculus`DSolve`"] 

answer = DSolve[{(x +e*f[x])*f'[x] + f[x] == 1, f[1]==2}, f[x],x]

f1[x_] =  Expand[f[x] /. answer[[1]]] /. Sqrt[x_]/y_ ->  Sqrt[Expand[x/y^2]]

	(*--->   one can get:  *)

(*-----------------------------------------------------------
                              2            2
           x         2 e + 4 e  + 2 e x + x
Out[36]= -(-) - Sqrt[-----------------------]
           e                    2
                               e
------------------------------------------------------------*)


	(*---> 1.- How can one use := instead of = in the f1[x_] definition *)
	(*---> 2.- Why Expand does not work inside Sqrt[...]                *)



Sergio Rojas
E-mail: sergio at scisun.sci.ccny.cuny.edu



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