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Re: Is there a better way to do a 3D List Plot?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg7385] Re: Is there a better way to do a 3D List Plot?
*From*: tburton at cts.com (Tom Burton)
*Date*: Fri, 30 May 1997 01:19:34 -0400 (EDT)
*Organization*: Brahea Consulting
*Sender*: owner-wri-mathgroup at wolfram.com
On 27 May 1997 10:29:40 -0400, in comp.soft-sys.math.mathematica you wrote:
>I have a list of data that I would like to plot
>that looks like:
>
>ResistMap3D1 =
> {{-1260,0,5060},{-840,0,5048},{-420,0,5032},{0,0,5046},{420,0,5041},{840,0,
> 5046},{1260,0,5052},{0,-1260,5047},{0,-840,5023},{0,-420,5037},{0,420,
> 5037},{0,840,5031},{0,1260,5056},{-840,840,5057},{840,840,5061},{
> 840,-840,5048},{-840,-840,5047},{-420,420,5037},{420,420,5033},{
> 420,-420,5034},{-420,-420,5036}};
>
>It's format it {x,y,z}.
>
>The only way I know of to plot this is:
>
>Resistpp =
> Show[Graphics3D[Point[{-1260,0,5060}]],Graphics3D[Point[{-840,0,5048}]],
> Graphics3D[Point[{-420,0,5032}]],Graphics3D[Point[{0,0,5046}]],
> Graphics3D[Point[{420,0,5041}]],Graphics3D[Point[{840,0,5046}]],
> Graphics3D[Point[{1260,0,5052}]],Graphics3D[Point[{-420,420,5037}]],
> Graphics3D[Point[{420,420,5033}]],Graphics3D[Point[{420,-420,5034}]],
> Graphics3D[Point[{-420,-420,5036}]],Graphics3D[Point[{-840,840,5057}]],
> Graphics3D[Point[{840,840,5061}]],Graphics3D[Point[{840,-840,5048}]],
> Graphics3D[Point[{-840,-840,5047}]],Graphics3D[Point[{0,-1260,5047}]],
> Graphics3D[Point[{0,-840,5023}]],Graphics3D[Point[{0,-420,5037}]],
> Graphics3D[Point[{0,420,5037}]],Graphics3D[Point[{0,840,5031}]],
> Graphics3D[Point[{0,1260,5056}]],AspectRatio->1,ViewPoint -> {0,1,0}];
>
>Is there a better way? And I can't get the point size to be big enough
>to see. Is there a way to increase the size?
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>
Yes, you can instruct Graphics3D directly to make bigger points, but there are much better ways! First, a 3D scatterplot will accept a change in point size. The following expression makes pretty big points.
Needs["Graphics`Graphics3D`"]
ScatterPlot3D[ResistMap3D1,PlotStyle->PointSize[.02],BoxRatios->{1,1,1/3}]
You can also make a surface. It's just a bit of work because the points are not arranged in a 2D array. First, form triangles connecting the points in the x-y plane:
Needs["DiscreteMath`ComputationalGeometry`"]
trival=DelaunayTriangulation[ResistMap3D1/.{x_,y_,z_}->{x,y}]
This algorithm is apparently not robust. This pattern of points leads to a failure, and the resulting surface is not complete. So off the top of my head, I decided to jiggle the points a bit in the x-y plane:
trival=DelaunayTriangulation[
ResistMap3D1/.{x_,y_,z_}->{x+10Random[]-5,y+10Random[]-5}]
These points generate more complaints but a better triangulation. Then plot the surface.
TriangularSurfacePlot[ResistMap3D1,trival,BoxRatios->{1,1,1}]
Tom Burton
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