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Re: Is a solution possible to this exponential equation?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg7047] Re: [mg6994] Is a solution possible to this exponential equation?
*From*: "w.meeussen" <w.meeussen.vdmcc at vandemoortele.be>
*Date*: Sat, 3 May 1997 22:04:41 -0400 (EDT)
*Sender*: owner-wri-mathgroup at wolfram.com
At 14:48 1-05-97 -0400, Michael Hucka wrote:
>I have a pair of equations involving exponentials that I'd like to be able to
>solve for one of the variables, but I can't seem to find a way to do it. MMA
>3.0's Solve operator complains its usual complaint about the equation
>involving transcendental functions. Quite possibly there is no analytical
>solution, but I'd like to find out from the experts out there about what
>approaches one might try. The equations are as follows:
>
> 1/2 = kc * Exp[ -a * w^2 * x^2 ] - ks * Exp[ -a * b^2 * w^2 * x^2]
>
>where a and b are constants, and kc, ks, w and x are variables. There is an
>additional condition,
>
> kc - ks = Sqrt[ 1/2 ]
>
>So there are 2 equations and 4 unknowns. I'd like to solve this for w, or
>rather, to express w in terms of the other unknowns. The problem, of course,
>is that w is in the exponent of two of the terms.
>
>What is the right approach to take in cases like this? This is actually
>something I've come across before in my work, but haven't had much luck with.
>
>--
>Mike Hucka hucka at umich.edu http://www.eecs.umich.edu/~hucka University
> PhD to be, computational models of human visual processing (AI Lab) of
> UNIX systems administrator & programmer/analyst (EECS DCO) Michigan
>
>
>
hi,
look what happens if you substitute
rule1=ks-> kc - Sqrt[ 1/2 ]
rule2= Exp[ -a * w^2 * x^2 any_:1 ] -> u^any
it= 1/2 ==kc * Exp[ -a * w^2 * x^2 ] - ks * Exp[ -a * b^2 * w^2 * x^2]
it/.rule1/.rule2
****************************************************
1/2 == kc*u - (-(1/Sqrt[2]) + kc)*u^(b^2)
****************************************************
so you have in essence
alfa x^n + beta x + gamma ==0
no symbolic solution to that I'm afraid. Numerics go ok though.
if b and kc are constants with a known numerical value, you can solve for u
using NSolve. The rest is simple : you can take the log and find (w * x).
To separate w and x needs further conditions.
does this help any?
Dr. Wouter L. J. MEEUSSEN
eu000949 at pophost.eunet.be
w.meeussen.vdmcc at vandemoortele.be
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