Mathematica 9 is now available
Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
1997
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 1997

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Integrate and Distribution over terms

  • To: mathgroup at smc.vnet.net
  • Subject: [mg9304] Re: [mg9255] Integrate and Distribution over terms
  • From: David Withoff <withoff>
  • Date: Mon, 27 Oct 1997 02:47:16 -0500
  • Sender: owner-wri-mathgroup at wolfram.com

> This problem came out of Mark Deckers experimentation with the
> UniformDistribution probability density function. (which returns a
> function with Sign's in it)
> 
> One of the basic lessons I learned in calculus is that
> Integrate[f[x]+g[x]]=Integrate[f[x]]+Integrate[g[x]].
> 
> I have an example where it appears that Mathematica hasn't figured that
> lesson out yet.
> 
> Integrate[Sign[x] Sin[x]/(2 Pi),{x,-4,4}] returns
> 
> 1/Pi-Cos[4]/Pi.
> 
> Integrate[Sign[x-Pi] Sin[x]/(2 Pi),{x,-4,4}] returns
> -1/Pi-Cos[4]/Pi.
> 
> But
> 
> Integrate[Sign[x] Sin[x]/(2 Pi)-Sign[x-Pi] Sin[x]/(2 Pi),{x,-4,4}]
> 
> takes about 5 times as long as either of the two preceding integrals and
> eventually returns itself.  ie Mathematica 3.0 can't do it.  It is as
> if Integrate didn't know it was supposed to distribute itself over the
> terms.  If I manually tell Integrate to distribute itself over the
> terms
> 
> Distribute[(Integrate[#1, {x, -4, 4}] & )[(Sign[x]*Sin[x])/(2*Pi) -
>     (Sign[-Pi + x]*Sin[x])/(2*Pi)]]
> 
> then it still takes a long time, but returns the correct answer, 2/Pi.
> 
> Am I correct that Integrate does not automatically distribute itself
> over the terms or is there another explanation for this behavior?  Is
> there some option or package that corrects this seeming flaw?  Thanks
> for any insight you could offer.

In answer to your question, here are a couple of examples where it would
not be a good idea to distribute integration over a sum

In[1]:= Integrate[1/Sin[x] - 1/x, {x, 0, Pi/2}]

            4
Out[1]= Log[--]
            Pi

In[2]:= Integrate[x^x/(x^x+1) + 1/(x^x+1), x]

Out[2]= x

The existence of such examples is the reason that Integrate does not
automatically distribute integration over a sum.  Sometimes, as in
these examples, distributing integration over a sum will generate
divergences or impossible integrals from an otherwise simple problem.

The main advantage of distributing integration over a sum is speed. With
that in mind, it is not only necessary to find an algorithm that can
figure out when it is ok to do this, but also to find a *fast*
algorithm, since taking too long to figure out whether or not it is ok
to distribute integration over a sum would defeat the original purpose.
Until such an algorithm is developed, using Map[Integrate[#, x] &,
expr] in place of Integrate[expr, x] is an easy way to get the speed
advantages with none of the complications.

Dave Withoff
Wolfram Research


  • Prev by Date: Re: Re: Horse Race Puzzle (fwd)
  • Next by Date: Re: Newbie question: big matrix calculations
  • Previous by thread: Integrate and Distribution over terms
  • Next by thread: Computer Algebra in Physics Research