Mathematica 9 is now available
Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
1997
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 1997

[Date Index] [Thread Index] [Author Index]

Search the Archive

How making arbitray matrices?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg9324] How making arbitray matrices?
  • From: "Kwag,Jae-Hwan" <c674362 at showme.missouri.edu>
  • Date: Mon, 27 Oct 1997 02:47:40 -0500
  • Organization: University of Missouri
  • Sender: owner-wri-mathgroup at wolfram.com

Hello,

This is Kwag.  I am studying NMR in Univ. of  Missouri-Columbia.
Nowdays I am using Mathmatica for my  project.  I have a question.  How
can I make  arbitray matries which have 2X2 dimensions, and they can be
used to one character;
Let me show you what I gona do;

The matrix II[x] can be written by
II[x]={{1,0},{0,1}}
II[y] ==85
II[z]==85
After I have used these values,  I  will try to solve my problems.  But
I have some trouble which can not use II[x],II[y]=85 directly in my
program  without the components such as {{1,0},{0,1}}.  Actually If I
put II[x],II[y] into my program on mathematica,  I want they can be
expressed by themselves and have the property of matrix. in) =(1 +
II[x] + II[y] + a II[z] + II[x].II[z]+ =85). ( 1 + II[x] + II= [y]

+ a II[z] + II[x].II[z]+ )
I want the output to be
out=Identity  Matrix+IIx + IIy+IIx.IIy+ IIx^2.IIy+ =85 After
calculateing, using //. IIx.IIy->1/4 Identity Matrix,=85, I will sove
this problem.
The mathematica can not  be accepted with my expression. Would you give
me advice how I make(declare) these matrices? 



  • Prev by Date: Q: Abs[1+f*I] assuming f>0 and real
  • Next by Date: Re: tessalation of a sphere
  • Previous by thread: Q: Abs[1+f*I] assuming f>0 and real
  • Next by thread: Questions re Style Sheets and Formatting (on the Mac)