Re: 1+Cos[x]Cosh[x]==0 ?
- To: mathgroup@smc.vnet.net
- Subject: [mg12148] Re: [mg12109] 1+Cos[x]Cosh[x]==0 ?
- From: "Sherman.Reed" <sherman.reed@worldnet.att.net>
- Date: Mon, 27 Apr 1998 01:46:31 -0400
Eddy, I plotted the equation 1+(Cos[x])*(Cosh[x]) to get approx values of the roots. I found xapprox to be {2,4.5,8,11,14,17}. I then used FindRoot[1+(Cos[x])*(Cosh[x]) ==0,{x,xapprox}] to get good values of the root. Sherman C. Reed sherman.reed@worldnet.att.net ---------- > From: Eddy Wibowo <ew4516@bristol.ac.uk> To: mathgroup@smc.vnet.net > To: mathgroup@smc.vnet.net > Subject: [mg12148] [mg12109] 1+Cos[x]Cosh[x]==0 ? > Date: Saturday, April 25, 1998 12:30 AM > > Hi everybody, > > How to solve "1 + Cos[x] Cosh[x] == 0"? I will probably need just the > first five, positive solution of "x". > > Many thanks before hand. > > -Eddy >