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Re: 1+Cos[x]Cosh[x]==0 ?

• To: mathgroup@smc.vnet.net
• Subject: [mg12148] Re: [mg12109] 1+Cos[x]Cosh[x]==0 ?
• From: "Sherman.Reed" <sherman.reed@worldnet.att.net>
• Date: Mon, 27 Apr 1998 01:46:31 -0400

Eddy,
I plotted the equation 1+(Cos[x])*(Cosh[x]) to get approx values of the
roots.  I found xapprox to be {2,4.5,8,11,14,17}.

I then used FindRoot[1+(Cos[x])*(Cosh[x]) ==0,{x,xapprox}] to get good
values of the root.

Sherman C. Reed
sherman.reed@worldnet.att.net
----------
> From: Eddy Wibowo <ew4516@bristol.ac.uk>
To: mathgroup@smc.vnet.net
> To: mathgroup@smc.vnet.net
> Subject: [mg12148] [mg12109] 1+Cos[x]Cosh[x]==0 ?
> Date: Saturday, April 25, 1998 12:30 AM
> 
> Hi everybody,
> 
> How to solve "1 + Cos[x] Cosh[x] == 0"?  I will probably need just the
> first five, positive solution of "x".
> 
> Many thanks before hand.
> 
> -Eddy
>