Mathematica 9 is now available
Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
1998
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 1998

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: List handling

  • To: mathgroup at smc.vnet.net
  • Subject: [mg15277] Re: List handling
  • From: "Allan Hayes" <hay at haystack.demon.co.uk>
  • Date: Thu, 31 Dec 1998 04:39:32 -0500
  • References: <76ciqj$o51@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Jorge Zickermann wrote in message <76ciqj$o51 at smc.vnet.net>...
>...........
>Having obtained the positions of certain selected elements from ListB, I
>want to substitute the corresponding elements in ListA by the
>corresponding elements in ListC.
> ..........

Jorge:

listA = {1, 2, 3, 4};
listB = {3, 2 , 5, 1};

Flatten[Position[listB, _?(# > 2 &)]]

{1, 3}

listA [[%]] = listB[[%]];

listA

{3, 2, 5, 4}

If the lists might not be of the same lenght then we can use

listB = {3, 2 , 5, 1, 7};

Cases[Flatten[Position[listB, _?(# > 2 &)]], _?(# <= Length[listA] &)]

{1, 3}


Allan

---------------------
Allan Hayes
Mathematica Training and Consulting
www.haystack.demon.co.uk
hay at haystack.demon.co.uk
Voice: +44 (0)116 271 4198
Fax: +44 (0)870 164 0565




  • Prev by Date: RE: How to use HoldForm within Module
  • Next by Date: stumping Integrate *correction*
  • Previous by thread: RE: List handling
  • Next by thread: Re: List handling