Re: List handling

*To*: mathgroup at smc.vnet.net*Subject*: [mg15269] Re: List handling*From*: Hans Staugaard Nielsen <hsn at imf.au.dk>*Date*: Thu, 31 Dec 1998 04:39:26 -0500*Organization*: Department of Mathematical Sciences, University of Aarhus*References*: <76ciqj$o51@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Jorge Zickermann wrote: > > listA= > > {1977.06,1977.06,1977.06,1977.06,1977.06,2047.77,2047.77,2047.77,2047.77,218 > 1.55,2181.55,2181.55,2244.73,2244.73,2244.73,2305.5,2305.5,2305.5,2305.5,236 > 3.92,2363.92,2363.92,2363.92,2363.92,2363.92,2363.92,2363.92,2363.92,2363.92 > ,2363.92} > > ListB= > > {0.684807,0.683029,0.665242,0.665242,0.664123,0.683029,0.665242,0.665242,0.6 > 64123,0.640339,0.640339,0.620329,0.640339,0.640339,0.620329,0.661684,0.64033 > 9,0.640339,0.620329,0.640339,0.622044,0.640339,0.621506,0.660996,0.640339,0. > 641006,0.640339,0.620935,0.640339,0.640339} > > ListC= > > {1971.45,1973.53,1994.29,1994.29,1995.6,2044.23,2065.,2065.,2066.3,2227.86,2 > 227.86,2251.22,2291.04,2291.04,2314.4,2326.89,2351.81,2351.81,2375.17,2410.2 > 2,2431.58,2410.22,2432.21,2386.11,2410.22,2409.44,2410.22,2432.88,2410.22,24 > 10.22} > > Position[ListB,_?(#>0.68&)] > > {{1},{2},{6}} > > Having obtained the positions of certain selected elements from ListB, I > want to substitute the corresponding elements in ListA by the > corresponding elements in ListC. In other words, I want to end up with; > > listA= > > {1971.45,1973.53,1977.06,1977.06,1977.06,2044.23,2047.77,2047.77,2047.77,218 > 1.55,2181.55,2181.55,2244.73,2244.73,2244.73,2305.5,2305.5,2305.5,2305.5,236 > 3.92,2363.92,2363.92,2363.92,2363.92,2363.92,2363.92,2363.92,2363.92,2363.92 > ,2363.92} > > Any help on how to do this is welcome. Thank you. > > Jorge Hi. How about somthing like this (listA[[#]]=listB[[#]])&/.Flatten[Position[ListB,_?(#>0.68&)]] Hans