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(a-b)/(c-d)=!=(b-a)/(d-c) ???

• To: mathgroup at smc.vnet.net
• Subject: [mg12964] (a-b)/(c-d)=!=(b-a)/(d-c) ???
• From: tdelling at ews.uiuc.edu (Tim Dellinger)
• Date: Sun, 28 Jun 1998 02:51:53 -0400
• Organization: University of Illinois at Urbana-Champaign
• Sender: owner-wri-mathgroup at wolfram.com

How come
(a-b)/(c-d) === (b-a)/(d-c)

returns False, i.e. TrueQ[ (a-b)/(c-d) =!= (b-a)/(d-c) ]  returns True,

but 

(a-b)/(c-d) === Simplify[ (b-a)/(d-c) ] 

returns True ???

Why does mere simplification change anything? I'm using Mathematica
3.0.?  on win95.


--
--
"Perhaps my most deeply rooted hobby is to understand         Tim
Dellinger
 the mechanisms of simple and familiar                   
tdelling at uiuc.edu
 natural phenomena." Irving Langmuir     
http://www.ews.uiuc.edu/~tdelling

• Follow-Ups:
  • Re: (a-b)/(c-d)=!=(b-a)/(d-c) ???
    • From: Sean Ross <seanross@worldnet.att.net>