[Date Index]
[Thread Index]
[Author Index]
Re: How: {{a,b},{1,2,3}} --> {{a,1},{b,2},{a,3}} ?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg14310] Re: How: {{a,b},{1,2,3}} --> {{a,1},{b,2},{a,3}} ?
*From*: Hans Staugaard <hans.staugaard at get2net.dk>
*Date*: Tue, 13 Oct 1998 01:21:25 -0400
*Organization*: Tele2 Internet Kunde
*References*: <6vf5es$dha@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
Michael Kubovy wrote:
>
> How do I get from {{a,b},{1,2,3}} to {{a,1},{b,2},{a,3}} ?
>
> Thanks,
> |\ /| / Michael Kubovy, Professor of Psychology, Dept of Psychology |
> \/ | / Univ of Virginia, Gilmer Hall, Charlottesville, VA 22903-2477 |
> |/\ office (B011): 804-982-4729, lab (B019): -4751, fax: -4766 | |
> \ HTTP://www.virginia.edu/~mklab/
I am not sure what you mean, but here is my intepretation of the
question:
Given a list containing list, form `mathcing' tuples, if a list runs
out,
cycle from beginning.
First i define a function pad:
pad[v:{__},n_Integer]:=
Take[Flatten[Table[v,{Ceiling[n/Length[v]]}]],n] /; n>Length[v]
pad[v:{__},n_Integer]:=
v /; n=Length[v]
and then
maketuples[m:{{__}..}]:=
With[{n=Max[Length[#]&/@m]},Transpose[pad[#,n]&/@m]]
this function should do the job, and will also work on things like
{{a,b},{1,2,3},{A,B,C,D}} yielding {{a,1,A},{b,2,B},{a,3,C},{b,1,D}}
Hans
Prev by Date:
**Re: Optimization packages for Mathematica: do they exist?**
Next by Date:
**Re: Solving simultaneous eqns**
Previous by thread:
**Re: How: {{a,b},{1,2,3}} --> {{a,1},{b,2},{a,3}} ?**
Next by thread:
**Re: 2D histogram of x,y values**
| |