Re: How: {{a,b},{1,2,3}} --> {{a,1},{b,2},{a,3}} ?

*To*: mathgroup at smc.vnet.net*Subject*: [mg14310] Re: How: {{a,b},{1,2,3}} --> {{a,1},{b,2},{a,3}} ?*From*: Hans Staugaard <hans.staugaard at get2net.dk>*Date*: Tue, 13 Oct 1998 01:21:25 -0400*Organization*: Tele2 Internet Kunde*References*: <6vf5es$dha@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Michael Kubovy wrote: > > How do I get from {{a,b},{1,2,3}} to {{a,1},{b,2},{a,3}} ? > > Thanks, > |\ /| / Michael Kubovy, Professor of Psychology, Dept of Psychology | > \/ | / Univ of Virginia, Gilmer Hall, Charlottesville, VA 22903-2477 | > |/\ office (B011): 804-982-4729, lab (B019): -4751, fax: -4766 | | > \ HTTP://www.virginia.edu/~mklab/ I am not sure what you mean, but here is my intepretation of the question: Given a list containing list, form `mathcing' tuples, if a list runs out, cycle from beginning. First i define a function pad: pad[v:{__},n_Integer]:= Take[Flatten[Table[v,{Ceiling[n/Length[v]]}]],n] /; n>Length[v] pad[v:{__},n_Integer]:= v /; n=Length[v] and then maketuples[m:{{__}..}]:= With[{n=Max[Length[#]&/@m]},Transpose[pad[#,n]&/@m]] this function should do the job, and will also work on things like {{a,b},{1,2,3},{A,B,C,D}} yielding {{a,1,A},{b,2,B},{a,3,C},{b,1,D}} Hans