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MathGroup Archive 1998

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Re: Summing over like elements

  • To: mathgroup at smc.vnet.net
  • Subject: [mg13881] Re: Summing over like elements
  • From: mefisher at my-dejanews.com
  • Date: Sun, 6 Sep 1998 02:55:21 -0400
  • Organization: Deja News - The Leader in Internet Discussion
  • References: <6sdb8i$peq@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Here is something that will work. I don't know how efficient it is.

list={{1, .5} , {2, .2} , {1, .1}}
Apply[{First[#1], Plus @@ #2}&, Transpose[#]]& /@
    Split[Sort[list], First[#1] == First[#2]&]

--Mark.


In article <6sdb8i$peq at smc.vnet.net>,
  "Mitchell Kaplan" <qmak at pipeline.com> wrote:
> I have a 2 column array.  Column 1 has some values, many of which are
> repeated.  Column 2 has probabilities of these values.
>
> I would like to sum the probabilities for each unique element in column
> 1. For example:
>
> {{1, .5} , {2, .2} , {1, .1}}  should give me:
>
> {{1, .6} , {2, .2}}
>
> I'm sure I can do this with a "Do" loop -- however it seems that in
> general "Do's" are pretty innefficient.
>
> Does anyone have any suggestions?
>
>                 Mitch
>
>


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