Re: how to replace a list of variables

• To: mathgroup at smc.vnet.net
• Subject: [mg14055] Re: [mg14017] how to replace a list of variables
• From: "Jens-Peer Kuska" <kuska at linmpi.mpg.de>
• Date: Fri, 18 Sep 1998 03:50:37 -0400
• Sender: owner-wri-mathgroup at wolfram.com

```Hi Shin-Ying,

can You explain what Your input mean ? The input

FindRoot[{x+y==10,x==y},{x,3},{y,3}] {{x->5,y->5}}

is due to the Mathematica manual interpreted as

Times[FindRoot[{x+y==10,x==y},{x,3},{y,3}], {{x->5,y->5}}]

and You get

{{x->5,y->5}}*{x->5.,y->5.}

that can not be used as an replacement rule and gives various errors. In
the case that You mean

FindRoot[{x+y==10,x==y},{x,3},{y,3}];{{x->5,y->5}}

that is (CompoundExpression[FindRoot[{x+y==10,x==y},{x,3},{y,3}],
{{x->5,y->5}}])
You must simply type it to get the correct result.

Hope that helps
Jens

-----Original Message-----
From: Shih-Ying Wu <wus at econ.lsa.umich.edu> To: mathgroup at smc.vnet.net
Subject: [mg14055] [mg14017] how to replace a list of variables

>Hi, I just got emails discussing how to assign a solution to a variable.
>However, the same approach doesn't work for the following similar
>question, in which the solution is a vector.
>
>FindRoot[{x+y==10,x==y},{x,3},{y,3}] {{x->5,y->5}}
>{x,y}={x,y}/.%
>
>Thanks.
>
>Shih-ying Wu
>
>
>
>

```

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