Re: PolynomialQ (wrong) behavior ?

• To: mathgroup at smc.vnet.net
• Subject: [mg19238] Re: [mg19199] PolynomialQ (wrong) behavior ?
• From: "Andrzej Kozlowski" <andrzej at tuins.ac.jp>
• Date: Wed, 11 Aug 1999 02:06:51 -0400
• Sender: owner-wri-mathgroup at wolfram.com

```In the message below I should have written (of course) "The expression 2x+1
is considered as a constant polynomial in y ..."
--
Andrzej Kozlowski
Toyama International University
JAPAN
http://sigma.tuins.ac.jp
http://eri2.tuins.ac.jp

----------
>From: "Andrzej Kozlowski" <andrzej at tuins.ac.jp>
To: mathgroup at smc.vnet.net
>To: Drago Ganic <drago.ganic at in2.hr> , mathgroup at smc.vnet.net
>Subject: [mg19238] Re: [mg19199] PolynomialQ  (wrong) behavior ?
>Date: Tue, Aug 10, 1999, 3:25 PM
>

> The function PolynomialQ is pretty simple minded. The expression 2x+1 is
> considered as a constant polynomial in x. A little more controversially, it
> is also considered as a constant polynomial in Sin[x], since it does not
> explicitely involve Sin[x] as variable. This is quite consistent with the
> behaviour of the derivative:
>
> In[1]:=
> D[2x + 1, y]
> Out[1]=
> 0
>
> In[2]:=
> D[2x + 1, Sin[x]]
> Out[2]=
> 0
>
>
> --
> Andrzej Kozlowski
> Toyama International University
> JAPAN
> http://sigma.tuins.ac.jp
> http://eri2.tuins.ac.jp
>
>
> ----------
>>From: "Drago Ganic" <drago.ganic at in2.hr>
To: mathgroup at smc.vnet.net
>>To: mathgroup at smc.vnet.net
>>Subject: [mg19238] [mg19199] PolynomialQ  (wrong) behavior ?
>>Date: Tue, Aug 10, 1999, 8:52 AM
>>
>
>> Hi,
>>
>> f = 2x +1
>>
>> PolynomialQ [ f, x ]
>> True
>>
>> That's OK. But why the following
>>
>> PolynomialQ [ f, y ]
>> True
>>
>> PolynomialQ [ f, Sin[x] ]
>> True
>>
>> Greetings,
>> Drago Ganic
>>
>>
>>
>>
>>
>>
>>

```

• Prev by Date: RE: Automatic Display in MatrixForm
• Next by Date: RE: Command for Stopping Notebook Evaluation?
• Previous by thread: Re: PolynomialQ (wrong) behavior ?
• Next by thread: Re: PolynomialQ (wrong) behavior ?