Re: Simple edit ...

*To*: mathgroup at smc.vnet.net*Subject*: [mg19328] Re: [mg19319] Simple edit ...*From*: BobHanlon at aol.com*Date*: Mon, 16 Aug 1999 02:14:57 -0400*Sender*: owner-wri-mathgroup at wolfram.com

Mike, z = (a + Sqrt[d + e])/(a Sqrt[d + e]); % // FullForm Times[Times[1, Power[Sqrt[Plus[d, e]], -1], Plus[a, Sqrt[Plus[d, e]]]], Power[a, -1]] Note in the FullForm that both terms in the denominator are actually included in Times with a negative power. Consequently, your pattern only matches the square root in the numerator. Use the following: z /. (d + e)^n_ :> L^(2*n) (a + L)/(a*L) Bob Hanlon In a message dated 8/15/99 4:19:17 AM, stokes at aris.net writes: >Consider the following examaple; > >z = (a+Sqrt[d+e])/(a Sqrt[d+e]) > >z //. Sqrt[d+e] ->L > >The replacement function only replaces the instance of Sqrt[d+e] in the >numerator and leaves the instance in the denominator alone. Why does >this not work and what is the work around? >