Re: Integrate[1/2+1/2 Erf[z],{z,-inf,0}]
- To: mathgroup at smc.vnet.net
- Subject: [mg21088] Re: Integrate[1/2+1/2 Erf[z],{z,-inf,0}]
- From: "Stephen P Luttrell" <luttrell at signal.dra.hmg.gb>
- Date: Sun, 12 Dec 1999 23:51:55 -0500 (EST)
- Organization: Defence Evaluation and Research Agency
- References: <5jf25g$g6k@smc.vnet.net> <7h7sn4$kmv@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Hendrik van Hees <h.vanhees at gsi.de> wrote in message news:7h7sn4$kmv at smc.vnet.net... > This is really a problem Mathematica seems not to be able to solve. The > problem is that it fails to calculate the limit > > inf(1-erf(inf)) for inf->Infinity. > > Doing this from hand with help of de L'Hospital's rule gives clearly 0. > Although I used Analytic->True within the Limit-command it didn't apply > this rule. You need to use the Calculus`Limit` package. In[1]:=Needs["Calculus`Limit`"]; In[2]:=Limit[x(1-Erf[x]),x->Infinity ] Out[2]=0 -- Stephen P Luttrell DERA Malvern