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Re: Block vs. Module
*To*: mathgroup at smc.vnet.net
*Subject*: [mg15692] Re: Block vs. Module
*From*: "Allan Hayes" <hay at haystack.demon.co.uk>
*Date*: Mon, 1 Feb 1999 14:54:12 -0500 (EST)
*References*: <78umac$982@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
Fred Simons wrote in message <78umac$982 at smc.vnet.net>...
>Eckhard,
>
>When using Block, there might be an interaction between the local
>variables defined in Block and the variables you use yourself. Have a
>look at the following example:
>
> In[1]:= f[x_] := Block[ {i}, Sum[x^i, {i, 1, 5} ]]
>
>In[2]:= f[a]
>
>Out[2]= \!\(a + a\^2 + a\^3 + a\^4 + a\^5\)
>
>In[3]:= f[i]
>
>Out[3]= 3413
>
>In this situation I would like to see a polynomial in i instead of a
>number. With Module, this cannot happen because Module creates names
>for the local variables that the user is supposed not to use:
>
>In[4]:= g[x_] := Module[ {i}, Sum[x^i, {i, 1, 5} ]]
>
>In[5]:= g[a]
>
>Out[5]= \!\(a + a\^2 + a\^3 + a\^4 + a\^5\)
>
>In[6]:= g[i]
>
>Out[6]= \!\(i + i\^2 + i\^3 + i\^4 + i\^5\)
>
>If you are only interested in variables that have numerical values, you
>can safely use Block instead of Module.
>
>Hope this helps,
>
>
>Fred Simons
>Eindhoven University of Technology
Fred
It might be useful to analyse the evaluation of the Module version - it
is scoping that does the trick:
After
g[x_] := Module[ {i}, Sum[x^i, {i, 1, 5} ]]
The first step in the evaluation of
g[i].
should apparently generate the result of replacing x inside Module[...]
by i; that is
Module[ {i}, Sum[i^i, {i, 1, 5} ]]
which would not be what we want.
But because Module is a scoping construct, and in the the original
Module[...] the i in {i} is bound to the i in x^i, the replacement of
the x triggers a change of
the original i's to i$, so that we get
Module[ {i$}, Sum[i^i$, {i, 1, 5} ]]
Then Module replaces i$ in Sum[...] with i&n (where n is the current
vale of $ModuleNumber) and gives
Sum[i^i$n, {i, 1, 5} ]]
which then evaluates.
We can see this by using
TracePrint[g[i]].
We can use scoping alone (in a contrived way!)
Clear[g,a]
g[x_] :=( i_->Sum[x^i,{i,2}])[[2]]
g[a]
a + a^2
g[i]
i + i^2
The first step in evaluating g[i], including scoping, gives
( i$_->Sum[i^i$,{i$,2}])[[2]]
Allan
---------------------
Allan Hayes
Mathematica Training and Consulting
www.haystack.demon.co.uk
hay at haystack.demon.co.uk
Voice: +44 (0)116 271 4198
Fax: +44 (0)870 164 0565
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