       FindRoot question (number of variables)

• To: mathgroup at smc.vnet.net
• Subject: [mg15743] FindRoot question (number of variables)
• From: "Doug Webb" <D_Webb at prodigy.net>
• Date: Fri, 5 Feb 1999 03:42:38 -0500 (EST)
• Organization: Prodigy Services Corp
• Sender: owner-wri-mathgroup at wolfram.com

```Hello,
This is a simplified example of I problem I have run into with
FindRoot. Does anybody have any idea why it's doing what it is? And if
so, how I can make it do what I want, or some other work around? Thanks
for any info. Here's the example:

define a function that takes one input, and outputs two results:

r[x_] := {x, x^2}

It does what's expected:

r
{4,16}

Now, find a solution using FindRoot:

FindRoot[ r[x] == {5, 25}, {x, 2}]

returns an error (rather than the obvious answer of x->5):

FindRoot::"frnum":
"Function {{-3., -21.}} is not a length 1 list of numbers at {x} =
{2.}."

It seems that FindRoot REQUIRES you to solve for as many variables as
your function returns. Even though when entered seperatly, r == {5,
25} returns "true". Why? Any ideas? Or any ideas how to get around this
"feature" of FindRoot? Thanks for any input.

Doug
D_Webb at prodigy.net
Douglas.S.Webb at maf.nasa.gov

```

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