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MathGroup Archive 1999

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Re: Concurrent Curve Fitting...

  • To: mathgroup at smc.vnet.net
  • Subject: [mg18577] Re: [mg18562] Concurrent Curve Fitting...
  • From: Ken Levasseur <Kenneth_Levasseur at uml.edu>
  • Date: Tue, 13 Jul 1999 01:01:19 -0400
  • Organization: UMass Lowell Mathematical Sciences
  • References: <199907100618.CAA03020@smc.vnet.net.>
  • Sender: owner-wri-mathgroup at wolfram.com

Robert:

You say the {xm,ym} are specific to the data set, but are they know or
are you free to select them?  If they are known, then this appears to be
a fairly routine "mixed approximation" problem.  I did a little bit of
research in this area in my disertation (several years before
Mathematica) and I think that there may be some known algorithms to
solve the problem.  You might want to check the Journal of Approximation
Theory for references. If the {xm,ym} are not fixed, it seems like an
interesting (and more difficult problem)

Ken Levasseur
Math. Sci.
UMass Lowell

Robert Carneim wrote:
> 
> Can anyone help me?
> 
> Here's what I want to do:
> 
> I have two sets of data which are related in such a way that, when plotted,
> they should have the same shape (or I want to force the curve fits to have
> the same shape), but at a different location.
> So, for example (and simplicity} suppose I have two sets of data which can
> be fit by lines, y=mx+b. I want to fit data set 1 to (y-y1)=m(x-x1)+b, and
> data set 2 to (y-y2)=m(x-x2)+b, where m and b are common and xn and yn are
> specific to the data set.
> This is a fairly easy to do indirectly, even by hand, but is there a way to
> get Mathematica to do this directly, i.e., finding the two curve fits
> concurrently? Obviously, I'm trying to do this for much more complex models.
> 
> Any input would be appreciated.
> 
> Thanks,
> -rdc.


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