       Re(2): RE: ExpIntegralEi

• To: mathgroup at smc.vnet.net
• Subject: [mg18681] Re(2): [mg18491] RE: [mg18463] ExpIntegralEi
• From: Andrzej Kozlowski <andrzej at tuins.ac.jp>
• Date: Thu, 15 Jul 1999 01:46:01 -0400
• Sender: owner-wri-mathgroup at wolfram.com

```I have had an interesting exchange with Hendrik van Hees concerning this
problem (one of his messages to me is included below). I think he has
produced the clearest explanation of the problem involved in symbolic
integration in this case. However, I do not agree with his suggestion
that the "symbolic answer" is as correct or incorrect as the numerical
one. In my opinion, there is no ambiguity here: the numerical answer is
right. As this seems to raise faily interesting issues relating  to both
mathematics and Mathematica I would like to try to explain this a little
more precisely. ( However, I have to first say that I am treading on thin
ice as this area is not my speciality and my knowledge does not go beyond
what would be expected of any professional mathematician in an area in
which he has never worked i.e. almost nil).

An integral like the one considered here is simply an integral of a
complex valued function over a measurable subset of R^2.  This is just a
special case of a more general concept of an integral of a function with
values in a Banach space (called a Bochner integral) and evaluating it
simply amounts to evaluating its real and imaginary parts separately and
taking the resulting complex number. All that is required for such an
integral to be well defined is that the real and imaginary parts of the
function  be integrable real functions. Such an integral can always quite
anambigiously  be evaluated simply by evaluating its real and imaginary
parts separately. Each of these can be reduced two repeated comptation of
ordinary integrals by Fubini's theorem:

Thus with

In:=
c2 = -0.05018627683354541 - 0.153047656745338 I;
In:=
c3 = -0.7828709924214918 + 0.2780791279205129 I;
In:=
c5 = -0.6758555487562639 - 0.04753624179417532 I;

In:=
f[x_, y_] := Exp[beta*c2 + s*(c3 + beta*c5)]
In:=
f1[x_, y_] := Re[f[x, y]]
In:=
f2[x_, y_] := Im[f[x, y]]

We get:

In:=
NIntegrate[f[x, y], {s, 0, 1}, {beta, 0, 1}]
Out=
0.587252 + 0.0191685 I

In:=
NIntegrate[f2[x, y], {s, 0, 1}, {beta, 0, 1}]
Out=
0.0191685

In:=
NIntegrate[f1[x, y], {s, 0, 1}, {beta, 0, 1}]
Out=
0.587252

All these computations are instantenous and there are no ambiguities or
singularities involved, since the functions are continuous and thus
integrable. There is no need for complex analysis here, both the
integrals of f1 and f2 can be computed as ordinary Lebesgue integrals on R^2.

However, ths situation is quite different when we try to use symbolic
integration. Mathematica is unable to calclulate Integrate[f1[x, y], {s,
0, 1}, {beta, 0, 1}] or Integrate[f2[x, y], {s, 0, 1}, {beta, 0, 1}]:

In:=
Integrate[f1[x, y], {s, 0, 1}, {beta, 0, 1}]
Out=
Integrate[Re[Power[E, (-0.0501863 - 0.153048 I) beta +

(-0.782871 + 0.278079 I -

(0.675856 + 0.0475362 I) beta) s]], {s, 0, 1},

{beta, 0, 1}]

Instead of viewing the integral as essentially two independent real
integrals Mathematica considers Exp as an analytic function in the
complex plane and tries to express the integral in terms of special
functions which are themselves defined as integrals in the complex plane.
However, as these function are not themselves analytic but have branch
cuts this introduces ambiguities in the answer. These ambiguities however
are not genuine, they result merely from the need to express the answers
in terms of already defined functions. One can see what happens by
considering the Henrik's computations below:

In:=
Clear[c2, c3, c5]

In:=
Integrate[Exp[beta*c2 + s*(c3 + beta*c5)], {s, 0, 1}] // Simplify
Out=
beta c2        c3 + beta c5
E        (-1 + E            )
-----------------------------
c3 + beta c5

This is function has a simple pole at c3=-beta*c5 . Numerical integration
of such a function shoudl noto cause any problem as long as c2 and c5 are
not both zero, but symbolic integration leads to new complications:

In:=
Integrate[(E^(beta*c2)*(-1 + E^(c3 + beta*c5)))/
(c3 + beta*c5), {beta, 0, 1}]
Out=
c2 c3                  c2 c3 + c3 c5
ExpIntegralEi[-----] - ExpIntegralEi[-------------]
c5                         c5
--------------------------------------------------- -
(c2 c3)/c5
E           c5

1                      c2 c3
-- (ExpIntegralEi[c2 + -----] -
c5                      c5

c2 c3 + c3 c5      (c2 c3)/c5
ExpIntegralEi[c2 + c5 + -------------]) / E
c5
Now we have an answer, but in terms of a function which has branch cuts.
This sort of answer is inherently ambiguous. With an unlucky choice of
the parameters it will produce numerically incorrect answer. In this I
agree with Henrik. However, this does no tchange the fact that the answer
one gets from symbolic integration is just simply wrong! The original
integral definitely is well defined and has a unique correct value.

On Tue, Jul 13, 1999, Hendrik van Hees <h.vanhees at gsi.de> wrote:

>Hello again,
>
>here is Mathematica's result:
>
>In:= Integrate[Exp[beta*c2+s*(c3+beta*c5)],{s,0,1},{beta,0,1}]
>
>                             c2 c3                  c2 c3
>          ExpIntegralEi[c2 + -----] - ExpIntegralEi[-----]
>                              c5                     c5
>Out= -(------------------------------------------------) -
>                               (c2 c3)/c5
>                           c5 E
>
>                   c3 (c2 + c5)                            c2 c3
>     ExpIntegralEi[------------] - ExpIntegralEi[c2 + c3 + ----- + c5]
>                        c5                                  c5
>>    -----------------------------------------------------------------
>                                  (c2 c3)/c5
>                              c5 E
>
>In:= Simplify[%]
>
>                              c2 c3                  c2 c3
>Out= -((ExpIntegralEi[c3 + -----] - ExpIntegralEi[-----] +
>                               c5                     c5
>
>                       c2 (c3 + c5)                            c2 c3
>>        ExpIntegralEi[------------] - ExpIntegralEi[c2 + c3 + ----- +
c5]) /
>                            c5                                  c5
>
>            (c2 c3)/c5
>>      (c5 E          ))
>
>This function is not unique because ExpIntegralEi has a branch cut along
>the negative real axis. Thus it is an analytic function in the right
>half plane of its argument. Thus if the combinations of the constants
>c2,c3,c5 are on the other (left) half plane its value is not unique. One
>must specify on which sheet of the Riemann surface you want to evaluate
>
>The reason is simply seen. If you take the inner integral for its own it
>results:
>
>In:= Integrate[Exp[beta*c2+s*(c3+beta*c5)],{s,0,1}]//Simplify
>
>         beta c2        c3 + beta c5
>        E        (-1 + E            )
>Out= -----------------------------
>                c3 + beta c5
>
>Thus if along the path of integration for beta (beta goes along the real
>axis from 0 to 1 in the outer integral) the denominator becomes 0 there
>is a ambiguity and this is the reason for the above mentioned branch
>cut. Thus the values you get out from NIntegrate could eventually depend
>on the gridding you take for integrating. I think one can check this
>explicitly with the given definite values of the parameters. But these I
>have to look up first.
>
>Greetings,
>
>--
>Hendrik van Hees		Phone:  ++49 6159 71-2755
>c/o GSI-Darmstadt SB3 3.162	Fax:    ++49 6159 71-2990
>Planckstr. 1			mailto:h.vanhees at gsi.de
>

Andrzej Kozlowski
Toyama International University
JAPAN
http://sigma.tuins.ac.jp/
http://eri2.tuins.ac.jp/

```

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