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Re: Sqrt[Sin^2(x)]=Sin(x)....????

  • To: mathgroup at smc.vnet.net
  • Subject: [mg16547] Re: [mg16329] Sqrt[Sin^2(x)]=Sin(x)....????
  • From: "Dale Horton" <daleh>
  • Date: Tue, 16 Mar 1999 04:00:19 -0500
  • Organization: Wolfram Research, Inc.
  • References: <7c58ve$7m8@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

a is only treu if a is a non-negative Real.
Abs[a] is only true if a is Real.

In general, Sqrt[a^2] is the only correct result. This why Mathematica
leaves it
unevaluated. PowerExpand is for people who don't want to mess with these
issues.

"PowerExpand also converts (a^b)^c to a^(b c)

The transformations made by PowerExpand are correct in general only if c is
an integer or a and b are positive real numbers. "

In this case, b is 2 and c is 1/2.

-Dale

Ranko Bojanic wrote in message <7c58ve$7m8 at smc.vnet.net>...
>
>
>The result returned by Mathematica
>
>In[1]:= Sqrt[a^2]//PowerExpand
>Out[1]= a
>
>is clearly correct only if a is a nonnative number.
>The only correct answer should be
>
>In[2]:= Sqrt[a^2]//PowerExpand
>Out[2]= Abs[a]
>
>Regards,
>Ranko
>
>> Alessandro Agresti <agresti at fi.infn.it> schrieb:
>
>>> Can I get the following result:
>>> Sqrt[Sin^2(x)]=Sin(x) ???
>>> If so, how??
>>> Thanks You for Your BIG help.
>>> Alessandro Agresti
>
>> Alessandro,
>
>> Mathematica knows, that this isn't always true. But you can use
>> PowerExpand to get what you want:
>
>> In[1]=  Sqrt[Sin[x]^2]//PowerExpand
>> Out[1]= Sin[x]
>
>> es gruesst
>>      Peter
>
>> In a message dated 3/5/99 8:09:48 AM, agresti at fi.infn.it writes:
>
>>> Can I get the following result:
>>> Sqrt[Sin^2(x)]=Sin(x) ???
>>> If so, how??
>
>> Alessandro,
>
>> You have the exponent in the wrong position
>
>> Sqrt[Sin[x]^2] // PowerExpand
>> Sin[x]
>
>> Bob Hanlon
>
>> Alessandro,
>> let's hope you know what you are doing.
>
>> In[1]:= PowerExpand[Sqrt[Sin[x]^2] == Sin[x]]
>> Out[1]= True
>
>> Jurgen
>
>> Alessandro Agresti wrote:
>>
>>> Can I get the following result:
>>> Sqrt[Sin^2(x)]=Sin(x) ???
>>> If so, how??
>>> Thanks You for Your BIG help.
>>> Alessandro Agresti
>
>
>




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