Re: Starting values with FindRoot
- To: mathgroup at smc.vnet.net
- Subject: [mg20669] Re: Starting values with FindRoot
- From: Brian Higgins <bghiggins at ucdavis.edu>
- Date: Sun, 7 Nov 1999 02:10:05 -0500
- References: <7vrbfp$2hg@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Here is one way to do it:
In[28]:=
eq = Table[z[i]^2 == 2 i, {i, 2}]
myg = {{z[1], 1.5}, {z[2], 2.5}}
Apply[FindRoot[eq, ##] &, myg]
Out[28]=
{z[1]^2 == 2, z[2]^2 == 4}
Out[29]=
{{z[1], 1.5}, {z[2], 2.5}}
Out[30]=
{z[1] -> 1.41421, z[2] -> 2.}
Regrads, Brian
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