Re: Finding lengths of identical sequences in lists

• To: mathgroup at smc.vnet.net
• Subject: [mg20274] Re: [mg20240] Finding lengths of identical sequences in lists
• From: "David Park" <djmp at earthlink.net>
• Date: Sun, 10 Oct 1999 01:27:30 -0400
• Sender: owner-wri-mathgroup at wolfram.com

```Joel,

Check out the Split command. Map Length onto the result.

Length /@ Split[{3, 2, 2, 3, 3, 3, 1}]
{1, 2, 3, 1}

Length /@ Split[{{1, 3}, {2, 5}, {2, 5}, {3, 2}, {3, 2}, {3, 2}, {1, 3}}]
{1, 2, 3, 1}

David Park

>I am looking for a more elegant solution to the following. I have a
>list (a list of positions at consecutive times).  I wish to create a
>new list of the length of each sequence of consecutive identical
>members (including those of length 1).
>
>For example, for the list {3,2,2,3,3,3,1} I would create the list
>{1,2,3,1} because the first 3 appears once, followed by two 2's,
>etc. The lists I was working with contained a list of numbers
>(e.g. {{x1,y1},{x2,y2},...} rather than simple numbers. I accomplished
>this using a while loop, but I suspect there are better ways to do
>this using pattern matching or other approaches.
>
>Thanks much.
>
>
>------------------------------------------------------------------------------
>Joel W. Cannon                   |   (724)223-6146
>Dept. of Physics                 |
>Washington and Jefferson College |
>Washington, PA 15301             |
>
>
>
>
>

```

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