Re: Tangent

*To*: mathgroup at smc.vnet.net*Subject*: [mg20583] Re: [mg20568] Tangent*From*: BobHanlon at aol.com*Date*: Sat, 30 Oct 1999 14:54:56 -0400*Sender*: owner-wri-mathgroup at wolfram.com

You could calculate the function from its power series Series[ArcTan[x], {x, 0, 8}] \!\(\* InterpretationBox[ RowBox[{"x", "-", \(x\^3\/3\), "+", \(x\^5\/5\), "-", \(x\^7\/7\), "+", InterpretationBox[\(O[x]\^9\), SeriesData[ x, 0, {}, 1, 9, 1]]}], SeriesData[ x, 0, {1, 0, Rational[ -1, 3], 0, Rational[ 1, 5], 0, Rational[ -1, 7]}, 1, 9, 1]]\) Sum[-(-1)^n * x^(2n - 1)/(2n - 1), {n, 1, Infinity}] ArcTan[x] or you could check whether VB6 -- like VBA -- has the function Atn(number) Bob Hanlon In a message dated 10/30/1999 5:35:23 AM, morris at chch.planet.org.nz writes: >I am writing a computer program in VB6 and I need >to write is into code: > > -1 >Tan > >eg: > > -1 >Tan 0.8 = 38.66 > >Does anyone know how to write this? >