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MathGroup Archive 1999

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Re: Tangent

  • To: mathgroup at smc.vnet.net
  • Subject: [mg20583] Re: [mg20568] Tangent
  • From: BobHanlon at aol.com
  • Date: Sat, 30 Oct 1999 14:54:56 -0400
  • Sender: owner-wri-mathgroup at wolfram.com

You could calculate the function from its power series

Series[ArcTan[x], {x, 0, 8}]

\!\(\*
  InterpretationBox[
    RowBox[{"x", "-", \(x\^3\/3\), "+", \(x\^5\/5\), "-", \(x\^7\/7\), "+", 
      InterpretationBox[\(O[x]\^9\),
        SeriesData[ x, 0, {}, 1, 9, 1]]}],
    SeriesData[ x, 0, {1, 0, 
      Rational[ -1, 3], 0, 
      Rational[ 1, 5], 0, 
      Rational[ -1, 7]}, 1, 9, 1]]\)

Sum[-(-1)^n * x^(2n - 1)/(2n - 1), {n, 1, Infinity}]

ArcTan[x]

or you could check whether VB6 -- like VBA -- has the function 

    Atn(number)

Bob Hanlon

In a message dated 10/30/1999 5:35:23 AM, morris at chch.planet.org.nz writes:

>I am writing a computer program in VB6 and I need
>to write is into code:
>
>       -1
>Tan
>
>eg:
>
>      -1
>Tan    0.8 = 38.66
>
>Does anyone know how to write this?
>


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