Re: Out[1]=((5-Sqrt[5])/20 + (5+Sqrt[5])/20 ) == 1/2 ???
- To: mathgroup at smc.vnet.net
- Subject: [mg20056] Re: [mg19976] Out[1]=((5-Sqrt[5])/20 + (5+Sqrt[5])/20 ) == 1/2 ???
- From: BobHanlon at aol.com
- Date: Wed, 29 Sep 1999 03:33:20 -0400
- Sender: owner-wri-mathgroup at wolfram.com
Patrick, It appears to have converted to numerical calculation before simplifying. Use Simplify Simplify[( (5 - Sqrt[5])/20 + (5 + Sqrt[5])/20 )] == 1/2 True Bob Hanlon In a message dated 9/24/1999 5:56:11 AM, p_mclean at postoffice.utas.edu.au writes: >Can any one explain this behaviour??? > >hilbert% math >Mathematica 3.0 for Solaris >Copyright 1988-96 Wolfram Research, Inc. > -- Terminal graphics initialized -- > >In[1]:= ( (5-Sqrt[5])/20 + (5+Sqrt[5])/20 ) == 1/2 > >$MaxExtraPrecision::meprec: > $MaxExtraPrecision = 50. reached while evaluating > 1 5 - Sqrt[5] 5 + Sqrt[5] > -(-) + ----------- + -----------. Increasing the value of > 2 20 20 > $MaxExtraPrecision may help resolve the uncertainty. > > 5 - Sqrt[5] 5 + Sqrt[5] 1 >Out[1]= ----------- + ----------- == - > 20 20 2 >