Re: Simplification shortcomings?

• To: mathgroup at smc.vnet.net
• Subject: [mg24666] Re: Simplification shortcomings?
• From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
• Date: Fri, 4 Aug 2000 01:18:54 -0400 (EDT)
• Organization: Universitaet Leipzig
• References: <8lsutf\$27c@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```Hi,

In[]:=FullSimplify[(1 + Sqrt[5])/2 - Sqrt[(3 + Sqrt[5])/2]]
Out[]=0

Regards
Jens

Bob Harris wrote:
>
> Howdy,
>
> I'm a relative novice to Mathematica.  While working with it today, I had
> occasion to want to know if a result was equal to (1 + Sqrt[5])/2.  The
> result was shown as Sqrt[(3 + Sqrt[5])/2].  After some pancil and paper
> work, I figured out that these two are equal.  Or, I should say, that the
> former is one of the values that the latter can have.
>
> I was frustrated in my attempts to get Mathematica to answer that question
> for me.  Simplify[(1 + Sqrt[5])/2 - Sqrt[(3 + Sqrt[5])/2]] didn't provide
> any improvement.  Calculating this value to many decimal digits showed it
> was near zero (probably close enough that I could have applied the
> techniques shown in Scheinerman's recent article in American Mathematical
> Monthly).  The only way I got Mathematica to show the equality was to square
> both numbers;  Simplify[((1 + Sqrt[5])/2)^2 - (3 + Sqrt[5])/2] is zero.
>
> Is there any better way to do this?  I have some other, more complicated
> numbers that I need to compare.
>
> Thanks,
> Bob Harris

```

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