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Re: A Functional Programming Question


One way, though not terribly elegant, is the following:

In[1]:= eqns~Function[{eq, cf}, Map[#/cf & , eq], {Listable}]~{a, b, c}

Out[1]= {x == 0, y == 0, z == 0}

-Mark


David Park <djmp at earthlink.net> wrote in message
news:8mdm9v$5o7 at smc.vnet.net...
> Dear MathGroup,
>
> Suppose I have three equations.
>
> eqns = {a x == 0, b y == 0, c z == 0};
>
> I want to divide out the constants a, b, and c. I can do it this way:
>
> eqns[[1]] = (#1/a & ) /@ eqns[[1]];
> eqns[[2]] = (#1/b & ) /@ eqns[[2]];
> eqns[[3]] = (#1/c & ) /@ eqns[[3]];
> eqns
>
> {x == 0, y == 0, z == 0}
>
> Is there a simpler method for doing the calculation in one statement with
> functional programming, say using MapThread over eqns and {a,b,c}? Is
there
> any other simple approach?
>
> David Park
> djmp at earthlink.net
> http://home.earthlink.net/~djmp/
>
>



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