[Date Index]
[Thread Index]
[Author Index]
Re: solve f(x)=0, where f:Rn+1 -> Rn
*To*: mathgroup at smc.vnet.net
*Subject*: [mg26209] Re: solve f(x)=0, where f:Rn+1 -> Rn
*From*: Alois Steindl <Alois.Steindl+e325 at tuwien.ac.at>
*Date*: Sat, 2 Dec 2000 02:10:37 -0500 (EST)
*Organization*: Inst. f. Mechanics II, TU Vienna
*References*: <9074h5$b0j@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
Hello,
I don't know of a package for that matter in Mathematica, but there
exist programs in Fortran, eg. the package AUTO by Doedel.
Also Prof. Seydel (http://bifurcation.de) has a Fortran-package
BIFPACK, which he might send you.
Good luck
Alois
Pavel.Pokorny at vscht.cz writes:
> Dear Mathematica friends
>
> Is there a way in Mathematica 4.0 to solve (numerically) the problem
> f(x) = 0
> where f: R^{n+1} -> R^n,
> i.e. f has n+1 real arguments and n real results ?
>
> The solution is (under certain conditions on f)
> a curve in (n+1)-dim space.
>
> Example
> x^2 + y^2 - 1 = 0
> is a unit circle.
>
> This problem is called "continuation" in nonlinear system analysis
> see
> Seydel: Tutorial on Continuation
> Int.J.Bif.Chaos, Vol.1 No.1 (1991) pp 3-11.
>
> --
> Pavel Pokorny
> Math Dept, Prague Institute of Chemical Technology
> http://staff.vscht.cz/mat/Pavel.Pokorny
Prev by Date:
**Re: Implicit Derivatives**
Next by Date:
**Re: Implicit Derivatives**
Previous by thread:
**Re: Implicit Derivatives**
Next by thread:
**Re: solve f(x)=0, where f:Rn+1 -> Rn**
| |