Re: solve f(x)=0, where f:Rn+1 -> Rn

*To*: mathgroup at smc.vnet.net*Subject*: [mg26209] Re: solve f(x)=0, where f:Rn+1 -> Rn*From*: Alois Steindl <Alois.Steindl+e325 at tuwien.ac.at>*Date*: Sat, 2 Dec 2000 02:10:37 -0500 (EST)*Organization*: Inst. f. Mechanics II, TU Vienna*References*: <9074h5$b0j@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Hello, I don't know of a package for that matter in Mathematica, but there exist programs in Fortran, eg. the package AUTO by Doedel. Also Prof. Seydel (http://bifurcation.de) has a Fortran-package BIFPACK, which he might send you. Good luck Alois Pavel.Pokorny at vscht.cz writes: > Dear Mathematica friends > > Is there a way in Mathematica 4.0 to solve (numerically) the problem > f(x) = 0 > where f: R^{n+1} -> R^n, > i.e. f has n+1 real arguments and n real results ? > > The solution is (under certain conditions on f) > a curve in (n+1)-dim space. > > Example > x^2 + y^2 - 1 = 0 > is a unit circle. > > This problem is called "continuation" in nonlinear system analysis > see > Seydel: Tutorial on Continuation > Int.J.Bif.Chaos, Vol.1 No.1 (1991) pp 3-11. > > -- > Pavel Pokorny > Math Dept, Prague Institute of Chemical Technology > http://staff.vscht.cz/mat/Pavel.Pokorny