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Re: Little(?) problem: What is the formula ???
*To*: mathgroup at smc.vnet.net
*Subject*: [mg21941] Re: Little(?) problem: What is the formula ???
*From*: Dr Dan <drdanw at my-deja.com>
*Date*: Sat, 5 Feb 2000 00:49:16 -0500 (EST)
*References*: <87e194$s01@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
Here is the quick answer (Version 4 only):
WeightedSum[s_] := Tr[Apply[Times, s, {1}]];
UnweightedSum[s_] := Tr[s[[All,2]]];
WeightedFraction[s_] := WeightedSum[s]/UnweightedSum[s];
In[35]:=
serie2 = {{0.1, 100}, {0.12, 200}, {0.15, 300}};
WeightedFraction[serie2]
Out[36]=
0.131667
Sorry I don't have time to go into why this works today, but here is a
tip: In Mathematica, think in terms of "operations performed on a
list" rather than "operations performed in a loop."
In article <87e194$s01 at smc.vnet.net>,
"Nijntje ?" <a.vanrossem at bellt-gca.nl> wrote:
> Hello All !
>
> I have two "series" of data :
> The first serie are "normal values"
> The seccond serie represents a percentage(Value) of an amount
(Nominator)
>
> Serie 1)
> Value Nominator
> 100 1
> 150 1
> 125 1
>
> Serie 2)
> Value Nominator
> 10 100
> 12 200
> 15 300
>
> The Problem:
> ----------------------------------------------------------------------
----
> I want to find a GENERAL formula to calculate the SUM of these series,
> So a formula which gives the following results
>
> Serie 1) 365
> Serie 2) 13,1
>
> Explanation results:
> Serie 1) 100+150+125 = 375
>
> serie 2) 10% of 100 = 10
> 12% of 200 = 24
> 15% of 300 = 45
> So total amount = 600 and the fraction=79 so that is 13.1%
>
> What is the general formula (using value and nominator) ?????????
>
> Thank you very much !!!
>
>
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