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MathGroup Archive 2000

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Re: Product with p!=j

  • To: mathgroup at smc.vnet.net
  • Subject: [mg21723] Re: Product with p!=j
  • From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
  • Date: Wed, 26 Jan 2000 03:45:27 -0500 (EST)
  • Organization: Universitaet Leipzig
  • References: <86abkr$8k0@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Hi,

q[n_Integer] := Module[{ p, j},
                  Sum[
                   1/(Product[Subscript[k, p] - Subscript[k, j],
                        {p, 1, j - 1}]*
                      Product[Subscript[k, p] - Subscript[k, j], 
                       {p, j + 1, n}]), 
                  {j, 1, n}
                 ]
                ]

If[] constructions will work also.

Hope that helps
  Jens

guillerm at gugu.usal.es wrote:
> 
> Dear friends,
> I have the following problem:
> 
> q[n_]:= Sum[1/Product[Subscript[k, p] - Subscript[k, j], {p, 1, n}], {j, 1, n}], with p!=j
> 
> Any suggestions?.
> Thanks
> 
> ---------------------------------------------
> This message was sent using Endymion MailMan.
> http://www.endymion.com/products/mailman/


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