Units

*To*: mathgroup at smc.vnet.net*Subject*: [mg23718] Units*From*: "Enrique Cao" <cao at mundo-r.com>*Date*: Mon, 5 Jun 2000 01:09:13 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

Hi: I need help in order to solve this problem. I have the vector aceleration {3 t Meter/Second^2,t^2 Meter/Second^2}. This is a vector dependent of time (t). I want to get the position vector with initial conditions {x[0]==2 Meter,y[0]==5 Meter,x'[1]==2 Meter/Second,y'[1]==3 Meter/Second}. I do this with the follow expression: << Miscellaneous`Units` << Miscellaneous`SIUnits` DSolve[{x''[t]==3 t Meter/Second^2,y''[t]==t^2 Meter/Second^2, x[0]==2 Meter,y[0]==5 Meter,x'[1]==2 = Meter/Second,y'[1]==3 Meter/Second },{x[t],y[t]},t] The solution is {x[t]->(Meter(4 Second^2+ 8 Second t +t^3 ))/(2 Second^2), y[t]->Mter(3+(6 t)/Second+t^4/(12 Second^2))} The unit of position is Meter but the solution is not correct. How can I get the correct solution ?? Thank you very much Henrique cao at mundo-r.com