Mathematica 9 is now available
Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2000
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2000

[Date Index] [Thread Index] [Author Index]

Search the Archive

RE: Rookie question

  • To: mathgroup at smc.vnet.net
  • Subject: [mg23753] RE: [mg23658] Rookie question
  • From: "Higinio Ramos Calle" <higra at gugu.usal.es>
  • Date: Mon, 5 Jun 2000 01:09:48 -0400 (EDT)
  • References: <200005290309.XAA14632@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

----- Original Message -----
From: Jose M Lasso <jml at accessinter.net>
To: mathgroup at smc.vnet.net
Subject: [mg23753] [mg23658] Rookie question


> Hi,
>
> Sorry for my ignorance, but I have Mathematica for just 3 days, and I have
> a trouble, I try to calculate the following expression:
> Integrate[1/(2(1-x^2)^(1/2)+(1-x^2)),{x,0,1}], but Mathematica dont give
me
> an answer, the program return the original input, do u have any ideas. Thx
> in advance.Regards
>
> Jose M Lasso
>
> PS:Sorry for my english
>

You can use NIntegrate instead of Integrate when you have to deal with a
difficult integral.
But in this case it is possible to find the integral directly using a change
of variable, setting
x=Sin(t) the integral becomes Integrate[1/(2+Cos[t]),{t,0,Pi/2}] which is
easy to obtain.

Higinio Ramos




  • Prev by Date: Fwd: Global Font Size
  • Next by Date: MathLink data transfer time
  • Previous by thread: Re: Rookie question
  • Next by thread: joining lists.