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MathGroup Archive 2000

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Re: Rookie question

  • To: mathgroup at smc.vnet.net
  • Subject: [mg23695] Re: [mg23658] Rookie question
  • From: BobHanlon at aol.com
  • Date: Mon, 29 May 2000 12:24:24 -0400 (EDT)
  • Sender: owner-wri-mathgroup at wolfram.com

In a message dated 5/28/2000 11:27:38 PM, jml at accessinter.net writes:

>Sorry for my ignorance, but I have Mathematica for just 3 days, and I have
>a trouble, I try to calculate the following expression:
>Integrate[1/(2(1-x^2)^(1/2)+(1-x^2)),{x,0,1}], but Mathematica dont give
>me
>an answer, the program return the original input, do u have any ideas.

Using Version 4

Integrate[1/(2(1 - x^2)^(1/2) + (1 - x^2)), {x, 0, 1}]

Pi/(3*Sqrt[3])

% // N

0.6045997880780727

If your version can't do the symbolic integral, try using numeric integration

NIntegrate[1/(2(1 - x^2)^(1/2) + (1 - x^2)), {x, 0, 1}]

0.6045997895732339

NIntegrate[1/(2(1 - x^2)^(1/2) + (1 - x^2)), {x, 0, 1 - 10^(-15)}]

0.6045997619134842


Bob

BobHanlon at aol.com


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