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Re: Mathematica (plotting a point on a graph)

  • To: mathgroup at smc.vnet.net
  • Subject: [mg26016] Re: Mathematica (plotting a point on a graph)
  • From: dkeith at sarif.com
  • Date: Thu, 16 Nov 2000 03:43:03 -0500 (EST)
  • References: <8ur0p8$quo@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Narash,

Here is one way. Define a function Mathematica style, solve the second
derivative==0 and get the coordinates of the inflection point, then
plot the function with the point plotted as a graphics primitive using
the Epilog option to Plot.

Regards,

David




f[x_] := 2x^3 - 3x^2 - 12x

xInflection = y /. Solve[D[f[y], {y, 2}] == 0][[1]]

yInflection = f[xInflection]

Plot[f[x], {x, -5, 5},
  Epilog -> {PointSize[.02], Point[{xInflection, yInflection}]}]



In article <8ur0p8$quo at smc.vnet.net>,
  "Narésh R Ganta" <nganta82 at hotmail.com> wrote:
> I went to you Mathematica website, and I have a question. Here is my
> problem. If I have F(x)=2x^3-3x^2-12x and I found that the inflection
point
> to be (.5,-6.5), how can I plot F(x), and show the inflection point
on the
> same graph?
>
> Thanks
>


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