Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2000
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2000

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: ? D[f,{x,n}]

  • To: mathgroup at smc.vnet.net
  • Subject: [mg25548] Re: ? D[f,{x,n}]
  • From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
  • Date: Sat, 7 Oct 2000 03:35:52 -0400 (EDT)
  • Organization: Universitaet Leipzig
  • References: <8rjioe$oea@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Hi,

you should no change D[f,x] or D[f,{x,n}]  you should change the
definition of

Derivative[n][f][__]

and only use the unique version Derivative[1][f][__] in your case.

Regards
  Jens

Jack Goldberg wrote:
> 
> Hi folks,
> 
> I am touching up a package I have worked on for a number of years.
> Rather than send it off as is, I keep tweeking it to improve its
> usefulness.  I should know better...  My latest tweek leads me to
> a problem with  D[f,{x,n}].  Here's the story:
> 
> In my package I define a constant "flag" which I set true: flag = True.
> 
> Then I Unprotect D:  Unprotect[D]:  I want to modify f before the built-in
> D fires so I write a little program:
> 
>         D[f_,x_]/;flag := Block[ {flag=False},
>           D[ mySimplification[f],x]
>                 ]
> 
> So, what I think happens is this. Since flag = True and since Mathematica uses
> my definition of D before its own, this little snippet fires.  Block sets
> flag = False, mySimplification[f] fires, and my definition of D does not
> fire again (or I would be caught in a loop) so Mathematica's definition of D
> now works and I have accomplished my aim which is to simplify f before
> taking the derivative.  This seems to work.  However, this idea fails to
> work for  D[f,{x,n}]!  Here's my code:
> 
>         D[f_,{x_,n_}]/;flag := Block[ {flag=False},
>           D[ mySimplification[f],{x,n} ]
>                 ]
> 
> (Of course, the nature of mySimplification should be irrelevant.)
> 
> While trying to work out this problem, I discovered that I don't
> understand the difference between  D[f,x] and D[f,{x,1}].  If I
> alter the definition of D[f,x] have I also altered the definition
> of  D[f,{x,1}]?  How about the other way around?  If I alter the
> definiton of  D[f,{x,1}] does this alter the definition of D[f,x]?
> It seems as though they should be linked internally but if so,
> I can find no reference to this linkage. This not a mute point since
> I found that in trying to use mySimplification in both  D[f,x] and
> D[f,{x,n}] it is necessary to know what happens if a user chooses to
> write D[f,x] in the form  D[f,{x,n}].
> 
> Help is needed.  Thanks.
>


  • Prev by Date: Re: Marcum Q function
  • Next by Date: Re: List element manipulation
  • Previous by thread: RE:? D[f,{x,n}]
  • Next by thread: Re: ? D[f,{x,n}]