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MathGroup Archive 2000

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RE: powersum with a function with variable count of parameters

  • To: mathgroup at smc.vnet.net
  • Subject: [mg25280] RE: [mg25262] powersum with a function with variable count of parameters
  • From: "David Park" <djmp at earthlink.net>
  • Date: Tue, 19 Sep 2000 03:45:07 -0400 (EDT)
  • Sender: owner-wri-mathgroup at wolfram.com

Peter,

Map powers of 10 onto the arguments and then apply Plus.

powersum[args__] := Plus @@ (10^# &) /@ {args}

powersum[1, 2, 3]
1110

David Park
djmp at earthlink.net
http://home.earthlink.net/~djmp/ 

> -----Original Message-----
> From: Klamser [mailto:Klamser at t-online.de]
To: mathgroup at smc.vnet.net
> Hi,
> 
> how can I write a function f[x_,xi__]=10^x+10^xi, that returns
> f[1,2,3]->10^1+10^2+10 ^3.
> 
> When i use the above definition, I only get
> 
> 10^1+10^2^3
> 
> But I want to get
> 
> 10^1+10^2+10 ^3
> 
> Regrads, Peter
 


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