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Re: Integrate[[1/(1+x+x^5),{x,-Infinity,Infinity}]


Hi,

it is easy to find that (1+x+x^5) has a simple pole on the
real axes at

{x -> 1/3 - (2/(25 - 3*Sqrt[69]))^(1/3)/3 - 
    ((25 - 3*Sqrt[69])/2)^(1/3)/3}

and you will probably Infinity, with any system.

The indefined integral is calculated by

Integrate[1/((x - a)*(x - b)*(x - c)*(x - d)*(x - e)), x] /.
   Thread[{a, b, c, d, e} -> (x /. Solve[1 + x + x^5 == 0, x])]

Regards
  Jens

Zak Levi wrote:
> 
> Dear Mathematica experts,
> 
> There was some discussion of this integral in sci.math
> without clear answer to the question:
> 
> How to calculate
> 
> Integrate[[1/(1+x+x^5),{x,-Infinity,Infinity}]
> 
> in Mathematica? -preferably NOT in M4 version,
> simply because not all users have the latter one.
> 
> Thanks a lot,
> ZL


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