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Re: Integrate doesn't yield what I expect


Hi,

you expect AcrSin[] and get Log[]  - unfortunatly there isn't a solution
for it because every inverse trigonometric function has an logarithmic 
representation ;-) 

ArcSin[x] -> -I*Log[Sqrt[(1-x^2)]+I*x]  x^2<=1

because Sin[x]=Exp[I*x]-Exp[-I*x]/(2I)

You should look at the equations 4.4.26 -- 4.4.31 in Abramowitz/Stegun

> Can you also guide me to the best book with solved integrals? (best means
> number of integrals solved)

I. S. Granstein, I. M. Ryshik
"Table of Series, Products and Integrals"


Regards
  Jens

Gransteint
Borut L wrote:
> 
> Helo,
> 
> I am integrating a function which has the form
> 1/(x Sqrt[a x^2+b x+c]),
> where c<0 and delta=4 a c-b^2 <0.
> Matematica always returns same result (with Log, the one with delta>0),
> despite giving option Assumptions->{...}. I expect a result with ArcSin. Is
> there other way to treat such somplex integrals?
> 
> In my real assignemt I have an integral 1/(x^2 (a x^2+b x+c)^(3/2)) with
> same c and delta. I expect again something with ArcSin or ArcCos, but the
> Log is again yilded.
> 
> Can you also guide me to the best book with solved integrals? (best means
> number of integrals solved)
> 
> Thanks, Borut


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