MathGroup Archive 2001

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Laplace Transforms of piecewise continuous functions

  • To: mathgroup at
  • Subject: [mg28316] Re: [mg28292] Laplace Transforms of piecewise continuous functions
  • From: Jack Goldberg <jackgold at>
  • Date: Wed, 11 Apr 2001 02:00:56 -0400 (EDT)
  • Sender: owner-wri-mathgroup at


If a function  f  is defined over an interval, say [a,b], then 

is zero outside [a,b] and f inside.  So you can piece together functions f
and g as follows:


Besides the ease in contructing piecewise functions this way, Mathematica knows
how to integrate  f[x]*UnitStep[x-a].  One warning:  Expand before trying
to integrate so that Mathematica is faced with sums like f[x]*UnitStep[x-a].
Also, you need version 3.xx or higher otherwise you have to download a

Jack Goldberg

On Sat, 7 Apr 2001, Michael A. Powers wrote:

> Hi,
> The documentation isn't very clear on how to compute a Laplace Transform of
> a piecewise continuous function f(t).  Say I have a function f(t) such that:
> f(t) = {3 over 0<=t<2, -2 over 2<=t<3, 0 over 3 <=t}
> how can I use the LaplaceTransform[] function to compute this easily?
> (aside from separately integrating the pieces, and adding)
> Thanks,
> -Mike

  • Prev by Date: Re: implicit function
  • Next by Date: Re: newbie question about the symbol E
  • Previous by thread: Re: Laplace Transforms of piecewise continuous functions
  • Next by thread: Re: How to convert a list of functions in a list valued function